2x^2-(x+1/3)(x+3)=x^2+2

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Solution for 2x^2-(x+1/3)(x+3)=x^2+2 equation: 



2x^2-(x+1/3)(x+3)=x^2+2

We move all terms to the left:

2x^2-(x+1/3)(x+3)-(x^2+2)=0



Domain of the equation: 3)(x+3)!=0

x∈R



We add all the numbers together, and all the variables

2x^2-(+x+1/3)(x+3)-(x^2+2)=0

We get rid of parentheses

2x^2-x^2-(+x+1/3)(x+3)-2=0

We multiply parentheses ..

2x^2-x^2-(+x^2+3x+x^2+1/3*3)-2=0

We multiply all the terms by the denominator


2x^2*3*3)-x^2*3*3)-(+x^2+3x+x^2+1-2*3*3)=0

Wy multiply elements

1458x^5*3=0

We do not support expression: x^5

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